\newproblem{lay:7_1_6}{
  % Problem identification
	\begin{large}
	  \hspace{\fill}\newline
    \textbf{Lay, 7.1.6}
	\end{large}
	\\
  \ifthenelse{\boolean{identifyAuthor}}{\textit{Carlos Oscar Sorzano, Aug. 31st, 2013} \\}{}

  % Problem statement
	Determine if the matrix $A=\begin{pmatrix} 1 & 2 & 1 & 2 \\ 2 & 1 & 2 & 1 \\ 1 & 2 & 1 & 2 \end{pmatrix}$ is symmetric.
}{
   % Solution
	A matrix $A$ is symmetric if $A=A^T$. So one necessary condition to be symmetric is that $A$ is a square matrix. Since the matrix in the problem is not square, it cannot
	be symmetric.
}
\useproblem{lay:7_1_6}
\ifthenelse{\boolean{eachProblemInOnePage}}{\newpage}{}

